Exercicio De Ligacao Covalente
Resolving exercise about covalent bonding is mostly about electrons, but most people get stuck on formal charge and octet violations before they even start.
I've seen the same mistakes repeated across thousands of practice sheets. The process sounds straightforward — count valence electrons, place atoms, draw bonds, check octets — but the moment you hit a transition metal or an expanded octet, the whole thing falls apart. I spent three years grading introductory chemistry exams before I stopped being surprised by anything. Start by counting total valence electrons. This is where most errors come from. Sulfate is SO4 2, which means 6 from sulfur plus 24 from the four oxygens plus 2 from the negative charge, giving you 32 total. Students routinely forget the charge contribution. I always check by adding the group numbers and then adjusting for ionic charge. If your count is off by two, you've either miscounted or missed a charge. Once you have the total, draw the skeleton structure. Put the least electronegative atom in the center, which is usually not hydrogen or fluorine. Hydrogen never forms more than one bond. Fluorine never exceeds an octet and never acts as a central atom. Any exception to either rule means you placed something wrong.
Common pitfalls in exercicio de ligacao covalente
The expanded octet problem is the first real complication. Sulfur can hold more than eight electrons because it uses d-orbitals in period 3. Phosphorus does the same in PCl5. When you're solving an exercicio de ligacao covalente involving these elements, you don't force every atom to eight electrons. That's the most common wrong approach I see. You calculate bonds, distribute remaining electrons as lone pairs on outer atoms first, then place whatever is left on the central atom. Formal charge changes everything. Many textbooks present a single Lewis structure for sulfate as if it were definitive, but the real structure involves resonance with multiple valid arrangements. The formal charge on sulfur in the standard octet-compliant drawing is +2, which is high. If you form double bonds between sulfur and two of the oxygens, that charge drops to zero. That structure is actually closer to what computational chemistry shows. The downside is that some exam boards still insist on the octet-following version, so you need to know both and read the question carefully. I ran into this repeatedly with phosphate and nitrate. Nitrogen cannot expand its octet, so NO3 must follow the octet rule strictly and distribute formal charge through resonance. Phosphorus in PO4 3 can expand, and the zero-formal-charge structure with one double bond is lower energy. But again, some courses mark the expanded-octet answer wrong. Know your instructor's expectations before you commit to one representation.
Here is the actual procedure I use when time is limited. Count valence electrons, build the skeleton, place single bonds, subtract bonding electrons from the total, distribute remaining electrons as lone pairs starting from the outer atoms, check whether the central atom has an octet, and if it doesn't, convert lone pairs from adjacent atoms into double or triple bonds. Then recalculate formal charges for every atom. The structure with formal charges closest to zero is generally the most stable representation. The step where students lose the most points is skipping the formal charge check. A structure that satisfies the octet rule but gives sulfur a +2 charge and every oxygen a 1 charge is technically valid for introductory courses, but it is chemically misleading. You should always evaluate formal charge as a secondary verification step, not the primary one. Another issue that comes up constantly involves polyatomic ions. The total electron count must reflect the ion's charge. A 2 charge adds two electrons to the count. A 3+ charge removes three. This is basic but it is also the single most frequent arithmetic error in grading stacks. I recommend writing the ion charge separately on your scratch paper before you begin so you don't lose track of it mid-calculation.

For hypervalent molecules like SF6, the process is simpler than it looks. Six fluorine atoms surround one sulfur with single bonds, using 12 bonding electrons. The remaining 48 electrons go entirely as lone pairs on the fluorines, six per atom. Sulfur has 12 valence electrons in this structure, which is fine because it is in period 3. If you try to enforce an octet here, you end up with impossible structures. Hybridization and molecular geometry are usually tested alongside the Lewis structure. Once you have the correct structure, count electron domains around the central atom. Each single bond, double bond, triple bond, and lone pair counts as one domain. Four domains means sp3 hybridization and tetrahedral geometry. Three domains with one lone pair means trigonal pyramidal. Two domains with two lone pairs means bent. Memorizing this table takes about ten minutes and saves significantly more during an exam. There is a practical limitation that almost nobody warns students about. Lewis structures and VSEPR theory work well for main-group elements in the first three rows. They break down completely for transition metal complexes and for molecules where d-orbital participation is ambiguous. If your exercise includes something like Fe(CO)5 or a coordination complex, stop trying to draw a traditional Lewis structure. Use crystal field theory or ligand field theory instead. Forcing a Lewis diagram onto a transition metal compound produces nonsense, and exam graders who include these questions are usually testing whether you recognize when the method doesn't apply.
Some exercises also involve odd-electron molecules like NO or ClO2. These are radicals, and they cannot satisfy the octet rule for every atom. In these cases, you draw the structure with the unpaired electron on the least electronegative atom and accept that one atom will have seven electrons. The formal charge check still applies, but octet completion is not the goal. When practicing at home, use a systematic approach. Write the total electron count at the top of your paper in a large font. Work one step at a time. Do not skip the formal charge calculation. If your structure gives you fractional or large formal charges, go back and reconsider double bond placement. Most errors in an exercicio de ligacao covalente trace back to one of three things: wrong electron count, skipped formal charge check, or failure to consider resonance structures. If you want practice problems, standard textbooks like Chang's Chemistry or Brown, LeMay, and Bursten's Chemistry: The Central Science have extensive exercise sets in their bonding chapters. Online, Khan Academy and ChemLibreTexts offer free tutorials with worked examples. The ChemLibreTexts section on Lewis structures is particularly useful because it covers edge cases like expanded octets and radicals that most introductory sources skip over.
The biggest mistake students make is treating this as a memorization task rather than a procedure. It is a procedure. Follow the steps, verify with formal charge, and adjust when the octet rule conflicts with charge minimization. That is the entire method.

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